Consider the following sequence of reactions.
Assuming that the reaction proceeds to completion, then 137 mg of 4 -nitrotoluene will produce 
mg of 
. (Given molar mass in 
)
Text Solution
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Starting with 137 mg of 4-nitrotoluene ( 
).
Step 1: Reduction with 
converts 
to 
, producing 4 -aminotoluene 
.
Step 2: Acetylation with 
produces the acetamide intermediate, then bromination with 
adds bromine to the para position (ortho-para directing due to acetamide group), yielding 4-bromo- N -(4methylphenyl)acetamide with molecular formula 
and MW 
.
Moles of starting material 
.
Assuming complete reaction, moles of B produced 
.
Mass of B 
.
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